Below is given a description of a practical problem arising in the chemical process-industry. Model this problem in terms of a Linear programming problem. The model should be EXPLICIT meaning that you should give appropriate names to variables and constraints. Then both model and solver reports will make sense and will be interpreted easily. Solve the LP-models with a solver of your choice: PC-Prog, SIMPLEX, or better LINDO or CPLEX. See Dealing with LP-problems for further explanations.
Description
In a chemical plant six kettles are used for the production of several types of
oil and oil-products. In this market the prices of the produced goods are more
or less fixed. For each unit of product the variable cost, the selling price,
and upper and lower limits on possible sales are given in table 1.
The production process has the following features. For the production of one unit of OLIE one uses a quarter unit of the product TRAAN. And for the production of one unit of SM-08 one uses one unit of product SM-07. There are two ways to produce products EOR-44 and AMD-66. As they require different kettle capacities the distinct product types appear in the tables below separately. Each kettle is available for 1000 hours. There are 10 operators that each are available for 1000 hours for supervising the process. The number of hours one unit of product claims from a particular kettle is given in table 2.
The company hires you as a consultant to answer the following Het bedrijf stelt U als consulent de volgende MANAGERIAL QUESTIONS:
product name | variable cost | sales price | minimum sales | maximum sales ------------------------------------------------------------------------------------- CB-75 | 20 | 40 | 10 | 50 MO-80 | 96 | 100 | 0 | 100 VET-b | 75 | 80 | 10 | 100 SM-07 | 60 | 70 | 0 | 50 BAND | 27 | 30 | 0 | 250 OLIE | 20 | 25 | 5 | 150 PL-99 | 10 | 16 | 0 | 300 TRAAN | 73 | 81 | 10 | 400 EOR-44 | 6 | 18 | 0 | 20 AMD-66 | 9 | 23 | 0 | 500
product name | K1 | K2 | K3 | K4 | K5 | K6 | Operators -------------------------------------------------------------------- CB-75 | 50 | 0 | 0 | 0 | 0 | 0 | 100 MO-80 | 1 | 0 | 25 | 0 | 0 | 0 | 50 VET-b | 0 | 0 | 0 | 0 | 10 | 0 | 50 SM-07 | 0 | 0 | 0 | 0 | 9 | 0 | 25 BAND | 0 | 15 | 0 | 0 | 0 | 0 | 10 OLIE | 0 | 10 | 0 | 0 | 0 | 0 | 5 PL-99 | 1 | 0 | 0 | 1 | 0 | 0 | 10 TRAAN | 1 | 0 | 0 | 1 | 0 | 0 | 5 EOR-44A | 0 | 0 | 0 | 0 | 0 | 50 | 12 EOR-44B | 20 | 0 | 0 | 30 | 0 | 0 | 12 AMD-66A | 0 | 0 | 0 | 0 | 0 | 100 | 40 AMD-66B | 0 | 0 | 0 | 30 | 40 | 0 | 60