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I think ETM code have some problem

wangzhongcheng
wangzhongcheng
in ProM 6
in code \src\org\processmining\plugins\etm ETM.java file line 78 //Now store ALL the best trees double bestFitness = population.get(0).getFitness(); for (EvaluatedCandidate candidate : population) { if (candidate.getFitness() == bestFitness) { bestResults.add(candidate.getCandidate()); } else { break; } } do you want get a best trees? but I think you just get the first tree,and then you are break;

Comments

  • hverbeek
    hverbeek
    Dear,

    No, assuming that the candidates are sorted on fitness in descending order, you get all best results. The break applies for the first candidate that does not have the best fitness, but then all best results are already added.

    Kind regards,

    Eric.


  • wangzhongcheng
    wangzhongcheng
    he set the first tree is bestFitness value,and then he loop the population to Calculation the bestFitness,when it is equal to the bestFitness is add it,but does not it will stop,so I think it always add the first tree is stop the loop
  • hverbeek
    hverbeek
    No, if the first three trees all have the same fitness value, they will all be added, and the loop stops at the fourth tree, as it has another (lower) fitness value.
  • wangzhongcheng
    wangzhongcheng
    you mean is that we only take the value of the first few trees, but why don't sorted on fitness and take the largest Fitness tree，that is better
  • hverbeek
    hverbeek
    They ARE sorted on fitness. The best results are those process trees which DO have the largest fitness.
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